Counting 1 Number at a Time (VSBW Edition)

[Accelerated_Evolution]

The Universe we are living in

 

[Reiner04]

Sum of products of roots of the X⁵-8X⁵+7X⁴+5X³+X²+X+1=0 taken 1 at the time.

 

[Javenplayz253]

100 - 91

 

[Accelerated_Evolution]

Sum of products of roots of the X⁵-8X⁵+7X⁴+5X³+X²+X+1 taken 1 at the time.

 

[Reiner04]

Pacman!!!

 

[GarrixianXD]

Negative reciprocal of the Ramanujan summation.

 

[Reiner04]

Ordinate of maxima of function y = sqrt(x-1) + sqrt(123/2-x)

 

[Javenplayz253]

1 + 2 = 12

 

[Accelerated_Evolution]

24/2 + 4 x 5 - 30 + 1

 

[Reiner04]

Value of N such that N = {N: Nπ∈(13.5π,14.5π) and ∉ csc(inv)X restricted to 15th branch}

 

[Javenplayz253]

Fif + teen

 

[Reiner04]

n: nπ is ordinate of maxima of 16th branch of sec(inv)x.

 

[Javenplayz253]

Seventeen - one + one.

 

[Accelerated_Evolution]

Spoiler

18

 

[Javenplayz253]

Spoiler

18

Above the consent Age (aka 19)

 

[Reiner04]

My age.

 

[Javenplayz253]

My age.

What's 9 + 10?
21.
You stupid

 

[Accelerated_Evolution]

 

[Reiner04]

N: tan(inv)N(pi) = 0 where N(pi) is ordinate of 24th branch of tan(inv)X.

 

[Javenplayz253]

280 - 255

 

[James_Plays_4_Games]

 

[Accelerated_Evolution]

N: tan(inv)N(pi) = 0 where N(pi) is ordinate of 24th branch of tan(inv)X.

the result is 23, right?

 

[Reiner04]

Restart dayum.
i⁴

the result is 23, right?

How do you know if I'll tell u the right answer?

Value of tan(inv)X = 0 when X is integral multipleof pi. 1st branch of tan(inv)X is between -pi/2 to pi/2. Rest follows (2n+1)pi/2 trend with open intervals, So yeah unless my memory on graphs has betrayed me.

 

[Javenplayz253]

 

[Accelerated_Evolution]

How do you know if I'll tell u the right answer?

I was guiding myself by the "(Insert number here)th branch of tan(inv)X."

 

[James_Plays_4_Games]

I think you meant...

 

[Accelerated_Evolution]

 

[James_Plays_4_Games]

 

[Reiner04]

abscissa of centroid of triangle A(4,6) B(0,1) C(2,9)

 

[Brogeefrong]

sex but replace the e with i

 

[Brogeefrong]

ate

 

[KingNanaya]

Current page number

 

[AdamVhenJP]

iphone 12

 

[Accelerated_Evolution]

Iphone 14

 

[Accelerated_Evolution]

Iphone 16

 

[Accelerated_Evolution]

Basically an Iphone 18

 

[Accelerated_Evolution]

 

[Accelerated_Evolution]

 

[Accelerated_Evolution]

 

[Robo432343]