Calc help

[Mr._Propeller_Hat]

So, I'm trying to calc Bane breaking apart a concrete pillar, but the problem is, how do you get the pixels based off the lines over the footage?

Image 1

Image 2

 

[Mr._Propeller_Hat]

Bump

 

[Mr._Propeller_Hat]

Bump, anyone?

 

[Aguywhodoesthings]

Most editing programs should be able to display the width and length of the line somewhere in the corner

 

[Mr._Propeller_Hat]

Most editing programs should be able to display the width and length of the line somewhere in the corner

So basically you just crop them to that size?

 

[Aguywhodoesthings]

So basically you just crop them to that size?

if you use a line tool the program should be able to display the amount of pixels to you
for example if you use mspaint it would show how many pixels long and wide the line is in the bottom left corner

 

[Mr._Propeller_Hat]

if you use a line tool the program should be able to display the amount of pixels to you
for example if you use mspaint it would show how many pixels long and wide the line is in the bottom left corner

Got it, is this correct?

 

[Aguywhodoesthings]

Got it, is this correct?

Yeah looks fine

 

[Mr._Propeller_Hat]

Yeah looks fine

Alright, so, Bane's head height is 414px which equals to 0.1095375 m

The hole height is 911px so

911/414 * 0.1095375 = 0.241035417

The hole width is 497px which equals to 0.1314979167 m

But the hypotenuse is the problem, how do I find that?

 

[Aguywhodoesthings]

But the hypotenuse is the problem, how do I find that?

i have no idea

 

[Mr._Propeller_Hat]

i have no idea

Nvm that,

497/414 *0.1095375 = 0.131497917m

0.131497917/sin (45 deg) = 0.185966138

So, the hole volume equals to (0.241035417)/3*((0.185966138)^2/2) = 0.001389 m^3 = 1389 cm^3

Which is 140.740425 joules (I might be wrong)

What AP does that yield?

 

[Aguywhodoesthings]

assuming the pillar is made of concrete, which has a fragmentation value of 6J/cm3
1389 x 6J = 8334 joules
using the violent fragmentation value of 17J/cm3
1389 x 17J = 23613 joules
I'm not quite sure which value would be better to use
also i'm not sure what formula you're using to calculate the hole, i think calculating it as a cylinder would be better

 

[Mr._Propeller_Hat]

assuming the pillar is made of concrete, which has a fragmentation value of 6J/cm3
1389 x 6J = 8334 joules
using the violent fragmentation value of 17J/cm3
1389 x 17J = 23613 joules
I'm not quite sure which value would be better to use
also i'm not sure what formula you're using to calculate the hole, i think calculating it as a cylinder would be better

Found it, so the pillars are actually limestone.

So Using the end of the violent fragmentation

1389 * 140J = 194,940J

1389 * 50J = 69,450J