About Cell's AP

[TyranoDoom30]

Currently, we have Cell's Kamehameha at 1.048 KiloFOE over a calculation of his statement of destroying the solar system, a statement basically universally accepted by powerscalers

However, what is there to assume he is only affecting the distance between The Earth and the Sun, and not the entire range of the solar system? Given that the distance from Earth to Neptune (the farthest planet) is far higher than 1 AU, this would make an omnidirectional explosion to consume it all to be far higher than the current calc (Also btw in the video linked in the calc the explosion seems to take a far bigger range than 1 AU)

 

[TheTenno07]

All the answers are in this thread https://vsbattles.com/threads/cell-cannot-escape-baseline-yet-dragon-ball.178226/

 

[KLOL506]

Simple answer: Not worth the effort. Farther you go out, the more the energy dissipates, if you were to calculate the energy of the epicenter based on its edge destroying Neptune, you'd get a lesser destruction value and at the same time completely ignore that you wouldn't be able to destroy the sun with that energy. Inverse-square law be funny like that.

 

[TyranoDoom30]

Simple answer: Not worth the effort. Farther you go out, the more the energy dissipates, if you were to calculate the energy of the epicenter based on its edge destroying Neptune, you'd get a lesser destruction value and at the same time completely ignore that you wouldn't be able to destroy the sun with that energy. Inverse-square law be funny like that.

Are you sure? Because i did seen some calcs using ISL getting the feat up to the 900s of KiloFOE (And even 1 MegaFOE of Pluto is included since Pluto was thought to be a planet at the time Toriyama was writing it)

 

[KLOL506]

Are you sure? Because i did seen some calcs using ISL getting the feat up to the 900s of KiloFOE

Prolly extrapolating to incredible extremes. We don't allow ISL at those scales without being 100% certain there is a celestial object at that specific distance from the epicenter being blown up. Hell, we disavow ISL for small-ass explosions because they inflate the results to crazy amounts without any excessive destruction to their surroundings.

 

[TyranoDoom30]

We don't allow ISL at those scales without being 100% certain there is a celestial object at that specific distance from the epicenter being blown up.

Isn't the entire solar system (incluiding the sun and the planets) getting blown up, though? I might be erroneous here so if i am i would like to be provided an explanation

 

[KLOL506]

Isn't the entire solar system (incluiding the sun and the planets) getting blown up, though? I might be erroneous here so if i am i would like to be provided an explanation

Was more so talking about the BS 900 kiloFOE values.

But either way, ISL would take over regardless, and basic laws of gravitational binding energy would also have to be taken into consideration. You can ask @DontTalkDT about the specifics.

 

[DarkDragonMedeus]

Technically, the blast radius of a typical explosion that size would ultimately but much larger than the size of the solar system; the blast that reaches the sun would still be highly concentrated and still in the process spreading rapidly by the time it hits the sun.

 

[MeiouHades]

Currently, we have Cell's Kamehameha at 1.048 KiloFOE over a calculation of his statement of destroying the solar system, a statement basically universally accepted by powerscalers

However, what is there to assume he is only affecting the distance between The Earth and the Sun, and not the entire range of the solar system? Given that the distance from Earth to Neptune (the farthest planet) is far higher than 1 AU, this would make an omnidirectional explosion to consume it all to be far higher than the current calc (Also btw in the video linked in the calc the explosion seems to take a far bigger range than 1 AU)

An explosion that starts from earth and destroys Neptune is less potent than one that starts from earth and destroys the Sun. The Sun is over 99% of the mass of the entire solar system, so the outward explosion of such a magnitude from earth would already destroy Neptune and probably beyond. It's already accounted for in that value

 

[DarkDragonMedeus]

An explosion that starts from earth and destroys Neptune is less potent than one that starts from earth and destroys the Sun. The Sun is over 99% of the mass of the entire solar system, so the outward explosion of such a magnitude from earth would already destroy Neptune and probably beyond. It's already accounted for in that value

I think you meant to say "Starting from the sun and destroys Neptune" for the first one. But yeah, basically correct on the detail otherwise.