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VS Battles Wiki Forum

Chariot190
Chariot190
Like that? It very well might, what you'd do is find the width of the torn metal or what not, get it's cross sectional area. Then multiply it by the material's ultimate tensile strength (So something like these, 1, 2, 3, 4).

It can very well vary, but I know the pulling on chains can definitely hit some decent yields, though it obviously depends on the thickness and type of steel. Got a Batman and Guts chain rip at like Class 25 before so it can definitely get good shit (Though the steels in question were a bit high end).

So yes, it can get Class 5, it could also be higher, or lower but Class 5 is definitely a solid possibility.
DemonicDude
DemonicDude
what you'd do is find the width of the torn metal or what not
Can you use paint to mark the exact moment you are talking about. I believe after which I will pixel scale it's width ? and what's the cross sectional area formula ?
Chariot190
Chariot190
Ok so say you have a chain link, the cross section is the part that gets torn.

Like say you have a cake, and you cut the cake in half, the inside of the cake after splitting on each side is the cross section, you get the area of that.

For a chain, you want to diameter or the radius of the link, they're circular. So the cross section would be a circle using the width of it.

For example, say he broke a 1 inch thick chain link, that would get you 5.067cm2 for the cross sectional area.

Then you just find the material and the tensile strength, so say it's 1 ton per cm2.

1tf/cm2 x 5.067cm2 = 5.067 tons of force LS.

Kinda like that.

Can't screencap but


An example of what I mean, Batman tore the chain, get the chain width (the parts that were torn), get area of cross section, multiple by tensile.
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