I was thinking of using the meaning of a drill, given that we even have a metaphor. But I didn't know how correct it was. Then I'll add that as a high end to my calculation.
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Therefir
Oh right, he called this technique a grand drill.
Using 8.33 spins for the low-end (the current one is 8), 20.83 for the mid-end, and 33.33 for the high-end should work much better than the timeframes of 1, 1.5 and 2 seconds.
Ugarik said something in your blog about a rotational kinetic energy formula, but I though that was debunked ever since Iron Man's hellicarrier feat.
Using 8.33 spins for the low-end (the current one is 8), 20.83 for the mid-end, and 33.33 for the high-end should work much better than the timeframes of 1, 1.5 and 2 seconds.
Ugarik said something in your blog about a rotational kinetic energy formula, but I though that was debunked ever since Iron Man's hellicarrier feat.
Therefir
Wait, it wasn't actually debunk.
This means you would have to divide every result by 3 times its KE value.
This means you would have to divide every result by 3 times its KE value.
NikHelton
Why 8 spins if low end is 18 spins?
Therefir
The low-end is 18 spins over two seconds, meaning 9 per second, I said 8 by mistake.
8.33 should be the new low-end.
8.33 should be the new low-end.
NikHelton
E = (1,1778322 × 10^20 * 113,04^2)/2 = 7,5251944 × 10^23 joules = 179 Teratons = High 6-B;
This is the rotational energy formula and I think it makes more sense than my previous version. However, I have not heard a word about dividing by 3.
This is the rotational energy formula and I think it makes more sense than my previous version. However, I have not heard a word about dividing by 3.
NikHelton
Didn't we decide to go with 1 second on the frame I dropped?
Therefir
I proposed the drill RPM as those wind circles may not exactly mean the numbers of spins, and is not reliant on timeframes.
But it's fine either way, I imagine you are going to add a high-end of 33.33 spins per second as well. Might be fine with that end actually.
But it's fine either way, I imagine you are going to add a high-end of 33.33 spins per second as well. Might be fine with that end actually.
NikHelton
I'll ask Ugarik about dividing by 3 in the meantime, but it looks like in IM's calculation it's due to the shape of the blades, because Tony is closer to the center, where their speed is lower. Bad and Garou, on the other hand, repelled the blow "from the edge of the blade", that is, KE should be full-fledged.
NikHelton
Yes, I learned from Ugarik. There is no need to divide by 3, because we have already found the moment of inertia.
NikHelton
Can you tell me how to find the angle to determine the distance? The standard formula uses a tangent of 35 degrees. I want to measure the angle at which the base of the Centipede is located on page 8.
https://**********/read/gist/Z2lzdC...YWYyMGU1YTlhMDMwZDgxL3Jhdy9vcG0uanNvbg/159/1/
Therefir
No way you can use the distance formula to find SG's height in that panel, SG is almost completely vertical to the field of view.
This (page 11) and this (page 20) panels otherwise should be fine using 35 degrees.
The method of using 6666 legs is still going to give better results though.
This (page 11) and this (page 20) panels otherwise should be fine using 35 degrees.
The method of using 6666 legs is still going to give better results though.
NikHelton
Hi, I am updating the calculations for Sage and ENO and decided to use the Ugarik method from the Psyrochi calculation to find out how long the shock wave spread.
The math is fine, however, I got a result of more than 40,000 km, which is more than our equator. Can this be used?
The math is fine, however, I got a result of more than 40,000 km, which is more than our equator. Can this be used?
Therefir
At a distance of 40,000 kilometers the globe would be completely visible, as that's almost 4 times greater than the diameter of the Earth, you should probably ask Ugarik about this but I don't think it is a good idea.
Low level Clouds and cities also seem to be visible alongside the curvature of the Earth, meaning it's probably not usable for scaling, as it's not a true shot from space.
Low level Clouds and cities also seem to be visible alongside the curvature of the Earth, meaning it's probably not usable for scaling, as it's not a true shot from space.
NikHelton
I'm not talking about the height of observation, but about the distance over which the blow spread.
Now I will post a draft version of the calculations.
Now I will post a draft version of the calculations.
Therefir
Okay, link it to me when it's ready.
NikHelton
Ready
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Two chertovsky huge assholes and one very strong
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NikHelton
The formula by which I calculated the impact distance of Saitama is the same formula by which we calculated the size of the city Z and it was accepted.
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RIP Z City - One-Punch Man
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NikHelton
After checking the calculations, could you tell if it is accepted by PE?
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Orochi Gaia Canon PE
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For cordless drill drivers, speed ranges from 500 to 2000 RPM.
RPM is revolutions per minute, so that would be 8.33 to 33.33 spins per second, not that different from Sage Centipede's values.