- 12,757
- 15,218
We currently don't have a soil vaporization value in the Calculations page, so I calculated it myself.
I've seen some people using this calc but it's wrong.
First, the boiling point of 1200C comes from answers.com with the calc author admitting "soil should be somewhat similar I guess", which is not a real source. No mineral found in soil actually boils at 1200C. Quartz boils at 2904C, hematite at 3414C, feldspar at around 3500C. The 1200C figure does not correspond to any real phase transition.
Second, and most importantly, the latent heat of vaporization was completely ignored. Vaporization is not just heating a material to its boiling point. The latent heat of vaporization is the energy required to actually convert the material from liquid to gas, and it is typically the largest portion of the total energy cost. For SiO2, the latent heat of vaporization alone is 11,770 kJ/kg, which is nearly 10 times larger than the heating energy calculated in the original. Skipping this makes the calc fundamentally wrong as a vaporization calculation.
Third, soil was treated as a single homogeneous material. Soil is a mixture of multiple minerals with completely different thermodynamic properties. Using a generic Cp of 800 J/kg*K and a made up boiling point of 1200C does not represent any of the actual components of soil.
The correct approach is to calculate each major soil component separately. Soil is composed of roughly 40% quartz (SiO2), 20% feldspar, 15% kaolinite, 5% hematite, and 15% water by mass. Each component has its own specific heat, melting point, latent heat of fusion, boiling point, and latent heat of vaporization, and all of these must be included for a proper vaporization calculation.
Using the latent heat of vaporization for SiO2 of 11,770 kJ/kg sourced from a peer reviewed planetary impact study, and applying the full heating plus phase transition energy for each soil component, the correct vaporization energy for soil is approximately 24,700 J/cc for average soil moisture, compared to the 2,592 J/cc currently used. That is roughly 9.5 times higher than the standard value. I can blog this calc if we reach a conclusion.
Soil is composed of multiple materials, each requiring different amounts of energy to vaporize. The composition used is: 40% SiO2 (quartz), 20% feldspar, 15% kaolinite (clay mineral), 5% hematite (iron oxide), 15% water and organic matter, and 5% air (ignored).
Energy per cm3: 9,147,765 x 0.0027 = 24,699 J/cm3≈ 24,700 J/cm3
- Soil density: 2.7 g/cm3 (0.0027 kg/cm3)
- Starting temperature: 20C
- Soil density and specific heat: https://www.engineeringtoolbox.com/specific-heat-capacity-d_391.html
- SiO2 latent heat of vaporization (11,770 kJ/kg) and boiling point (3177 K / 2904C): https://agupubs.onlinelibrary.wiley.com/doi/full/10.1029/2012JE004082
- Specific heat: 730 J/kg*K
- Heating to melting point (1710C): 730 x (1710-20) = 1,233,700 J/kg
- Latent heat of fusion: 50,000 J/kg
- Heating from melting to boiling (2904-1710 = 1194C): 730 x 1194 = 871,620 J/kg
- Latent heat of vaporization: 11,770,000 J/kg
- Total SiO2: 13,925,320 J/kg
- Specific heat: 750 J/kg*K
- Heating to melting point (1220C): 750 x (1220-20) = 900,000 J/kg
- Latent heat of fusion: 100,000 J/kg
- Heating from melting to boiling (3500-1220 = 2280C): 750 x 2280 = 1,710,000 J/kg
- Latent heat of vaporization: 6,000,000 J/kg (estimated, experimental data scarce)
- Total feldspar: 8,710,000 J/kg
- Specific heat: 800 J/kg*K
- Heating to decomposition/vaporization (~3000C): 800 x (3000-20) = 2,384,000 J/kg
- Latent heat of fusion + vaporization: 5,200,000 J/kg (estimated)
- Total kaolinite: 7,584,000 J/kg
- Specific heat: 650 J/kg*K
- Heating to melting point (1565C): 650 x (1565-20) = 1,004,250 J/kg
- Latent heat of fusion: 209,000 J/kg
- Heating from melting to boiling (3414-1565 = 1849C): 650 x 1849 = 1,201,850 J/kg
- Latent heat of vaporization: 3,770,000 J/kg
- Total hematite: 6,185,100 J/kg
- Specific heat: 4186 J/kg*K
- Heating to boiling (100C): 4186 x (100-20) = 334,880 J/kg
- Latent heat of vaporization: 2,257,000 J/kg
- Total water: 2,591,880 J/kg
Energy per cm3: 9,147,765 x 0.0027 = 24,699 J/cm3≈ 24,700 J/cm3
I've seen some people using this calc but it's wrong.
First, the boiling point of 1200C comes from answers.com with the calc author admitting "soil should be somewhat similar I guess", which is not a real source. No mineral found in soil actually boils at 1200C. Quartz boils at 2904C, hematite at 3414C, feldspar at around 3500C. The 1200C figure does not correspond to any real phase transition.
Second, and most importantly, the latent heat of vaporization was completely ignored. Vaporization is not just heating a material to its boiling point. The latent heat of vaporization is the energy required to actually convert the material from liquid to gas, and it is typically the largest portion of the total energy cost. For SiO2, the latent heat of vaporization alone is 11,770 kJ/kg, which is nearly 10 times larger than the heating energy calculated in the original. Skipping this makes the calc fundamentally wrong as a vaporization calculation.
Third, soil was treated as a single homogeneous material. Soil is a mixture of multiple minerals with completely different thermodynamic properties. Using a generic Cp of 800 J/kg*K and a made up boiling point of 1200C does not represent any of the actual components of soil.
The correct approach is to calculate each major soil component separately. Soil is composed of roughly 40% quartz (SiO2), 20% feldspar, 15% kaolinite, 5% hematite, and 15% water by mass. Each component has its own specific heat, melting point, latent heat of fusion, boiling point, and latent heat of vaporization, and all of these must be included for a proper vaporization calculation.
Using the latent heat of vaporization for SiO2 of 11,770 kJ/kg sourced from a peer reviewed planetary impact study, and applying the full heating plus phase transition energy for each soil component, the correct vaporization energy for soil is approximately 24,700 J/cc for average soil moisture, compared to the 2,592 J/cc currently used. That is roughly 9.5 times higher than the standard value. I can blog this calc if we reach a conclusion.
Last edited: