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Two Questions (actually four but well)

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Things from a certain novel, the first one it's for curiosity and the second one for a possible LS upgrade.
  • The weigh of a starfish of three meters made of mercury?
    • The weigh of a starfish of teen meters made of mercury?
  • The LS for use a western sword of two kilometers?
    • The LS for use a western sword of thirteen kilometers?
 
Things from a certain novel, the first one it's for curiosity and the second one for a possible LS upgrade.
  • The weigh of a starfish of three meters made of mercury?
    • The weigh of a starfish of teen meters made of mercury?
  • The LS for use a western sword of two kilometers?
    • The LS for use a western sword of thirteen kilometers?
What is (LS)? I want to know.
 
i could be wrong so make a proper calc

the weight of the three meter starfish of mercury, assuming it is 1 meter wide and its five ends are equilateral triangles is
80784.446kg or 80.78 tons

the rest do it yourself.
What i did is i pixelscaled a normal star shape, got the average length of a triangle side and assumed that the center is a pentagonal prism.
This was a calc of 1 pentagonal prism and 5 triangular prisms made of solid mercury
 
The LS for use a western sword of two kilometers?
  • The LS for use a western sword of thirteen kilometers?
This is only a rough estimation based on other calcs I've seen:

A sword weighs on average 1.475 kg and is 115cm in length on average

2km is 200,000cm

13km is 1,300,000cm

Here is the formula for square cube law:

(Weight of smaller object) * (Length of larger object/length of smaller object)^3 = Weight of larger object

1.475kg * (200,000cm/115cm)^3 = 7.75869154 × 10^9 kilograms or 7.7587e9 kg or Class G

1.475kg * (1,300,000cm/115cm)^3 = 2.13073066 × 10^12 kilograms or 2.13e12 kg or Class T
 
i could be wrong so make a proper calc

the weight of the three meter starfish of mercury, assuming it is 1 meter wide and its five ends are equilateral triangles is
80784.446kg or 80.78 tons

the rest do it yourself.
What i did is i pixelscaled a normal star shape, got the average length of a triangle side and assumed that the center is a pentagonal prism.
This was a calc of 1 pentagonal prism and 5 triangular prisms made of solid mercury
Thanks, this is quite curious, maybe could be a calc to certain character.
This is only a rough estimation based on other calcs I've seen:

A sword weighs on average 1.475 kg and is 115cm in length on average

2km is 200,000cm

13km is 1,300,000cm

Here is the formula for square cube law:

(Weight of smaller object) * (Length of larger object/length of smaller object)^3 = Weight of larger object

1.475kg * (200,000cm/115cm)^3 = 7.75869154 × 10^9 kilograms or 7.7587e9 kg or Class G

1.475kg * (1,300,000cm/115cm)^3 = 2.13073066 × 10^12 kilograms or 2.13e12 kg or Class T
Thanks, this could be a big upgrade to Arifureta characters.
 
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