-
This forum is strictly intended to be used by members of the VS Battles wiki. Please only register if you have an autoconfirmed account there, as otherwise your registration will be rejected. If you have already registered once, do not do so again, and contact Antvasima if you encounter any problems.
For instructions regarding the exact procedure to sign up to this forum, please click here. -
We need Patreon donations for this forum to have all of its running costs financially secured.
Community members who help us out will receive badges that give them several different benefits, including the removal of all advertisements in this forum, but donations from non-members are also extremely appreciated.
Please click here for further information, or here to directly visit our Patreon donations page. -
Please click here for information about a large petition to help children in need.
Question about temperature change calcs
- Thread starter TheComet9
- Start date
Chritin
He/Him- 1,494
- 1,128
With temperature change calcs, there are two things you need to consider, which may or may not be applicable. One is the actual energy needed to change an object's temperature from one level to another. To determine this, you need three things: the mass of the object, the heat capacity (a constant physical property which expresses how much energy is needed to change the temperature of a kg of substance by a certain amount), and the change in temperature in Kelvin. That can all be expressed in this equation.
Energy = Object Mass * Heat Capacity (J/kg*K) * (Final Temp - Initial Temp)
The other thing that you need to consider is what's called the latent heat, or the energy actually needed to change an object from one physical state of matter to another. The units for this can vary, since there different thermodynamic values for things like melting (fusion), or vaporization. Normally though, these values are expressed in a certain amount of Joules over the quantity of a substance (kJ/kg, J/g, J/cm^3, etc.) You then just multiply that by whatever quantity you have, then add it to your result.
Now, looking at the calc you linked, I can't really tell what's being done exactly, but it does seem to fundamentally be the same idea. It's just expressed algebraically in a way I'm having trouble comprehending. Freezing calcs are also just generally weird because they involve removing energy from a system rather than adding it in, basically meaning you are working with a net negative amount of energy if you did it the way I did above (the initial temp would be higher than the final temp, causing a net negative amount of energy). In which case, they might've just written it in a way where they wouldn't have had to correct negative numbers
- 640
- 103
- Thread starter
- #3
They also got the specific heat of both vapor and ice, and they got an energy value from it, something that i didn't see in other freezing calcs
Chritin
He/Him- 1,494
- 1,128
I’m pretty sure this is cause they interpret the feat as freezing air, meaning that they have to calculate the energy needed to change phase from a gas to a liquid then a liquid to a solid.
(Kinda off topic, but I’m curious if there’s a way we could account for things like sublimation or other processes where phases change without an intermediate)
- 640
- 103
- Thread starter
- #6
I see people handling this by adding both of the latent heat and mass multiplied
Similar threads
