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VS Battles Wiki Forum

Drite77
Drite77
I might not be able to do it today and I might forget about it. Remember me tomorrow if I have not evaluated it by then
Ninkan12
Ninkan12
No worries thank you I will
Drite77
Drite77
Where did you get the formula for the Spherical Shell volume? I searched around and got different ones
Ninkan12
Ninkan12
I didn't, I'm pretty sure I just took the volume of the sphere at the top of the cloud layer (planet radius + cloud altitude + cloud thickness) and subtracted the volume of the sphere at the bottom of the cloud layer (planet radius + cloud altitude), since the difference between those two spheres is the volume occupied by the clouds.

I realise now I have failed to neglect that a mini cooper sized planet probably wouldn't have the same cloud thickness and altitude as earth, assuming that pixel scaling is the better option of the two
Drite77
Drite77
So perhaps that would be better to say you didn't use a Spherical Shell because that's an actual polyhedron with a volume formula to it, and just say what you did instead.

I think that assumption is fine
Ninkan12
Ninkan12
Sorry then my fault, I'll update the calc

Is there anything else wrong with it while I'm editing? And I'm assuming we're going with method 1 cause I'll delete method 2
Drite77
Drite77
If you can prove the size of the planet is inconsistent I would go with method 2
Ninkan12
Ninkan12
It's inconsistent by like a couple hundred centimeters at a time, not enough to really make a difference. Plus the inconsistencies come from when the planet has giant plants on it which could just be very large.
Drite77
Drite77
I would say a few meters is not inconsistent, yeah. So I would go with the 1st method
Ninkan12
Ninkan12
All updated
Drite77
Drite77
Do not post images, post the actual numbers in the calcs, the former makes it a bit harder to evaluate. And one thing I noticed just now, where did you get the density? We use different densities for the water content on Cumulus clouds then the one you're using
Ninkan12
Ninkan12
I can tell you where I got it from but I feel real stupid lol

I tried to reverse the density from the calc in references for common feats which comes out to 0.612kg/m^3 but I think I thought it was g/m^3

What value do we use and I'll fix it?

Also are you referring to the image where I scale the planet, if so I did not know I apologise
Drite77
Drite77
For condensation, we use this for cumulus

No, I'm talking about all of the calcs, they are images, not something typed in the blog. It is much easier to evaluate if the numbers are typed in the blog itself
Ninkan12
Ninkan12
Oh i see you're referring to the </math> function, I understand. Again I didn't know and I'll keep it in mind in future my apologies

It is done
Drite77
Drite77
You can use the average between the two densities instead of doing both the low and high end
Ninkan12
Ninkan12
Average took and updated
It actually knocks it down a tier lol
Drite77
Drite77
Ok, I'll admit, this is the first time I took an actual look at the calc, and I have to ask, why did you got the "kg/s" thing, if you're just using the full weight of the clouds? This should be the only thing left for you to respond me before I fully evaluate the calc, I checked everything else and nothing is out of the ordinary outside of that
Ninkan12
Ninkan12
Because the production of mass under the common feat? If I'm understanding things correctly
Drite77
Drite77
Notice how, on each example, they took the result of the mass divided by the timeframe to then multiply by the latent heat of water, you did not do that, you just used all of the weight instead
Ninkan12
Ninkan12
So instead of E = mLv I need to do E = ṁLv?
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