The official calculation blogs

[Antvasima]

Hello.

Our wiki navigation bar currently has two series of sections that overlap, "Guidelines: Policies" and "Featured: Information Blogs".

Basically, the official pages within the former section mainly focus on informing about standards used for calculations, but so do some of the blogs within the latter section, whereas most of them provide information about different fictional franchises.

This seems improperly organised, and I have noticed that this causes our members to be considerably less aware of the important information provided by the blogs. As such, I suggest that we copy the contents to official regular pages, and link to them within the "Guidelines: Policies" sections instead.

Would the rest of you find this acceptable?

The following pages would be included:

https://vsbattles.fandom.com/wiki/User_blog:Darkanine/Earthquake_Power_Chart

https://vsbattles.fandom.com/wiki/User_blog:Antoniofer/Explosion_Radious/Area

https://vsbattles.fandom.com/wiki/User_blog:Lina_Shields/Mountain_and_Island_level_requirements

NOTE: STAFF ONLY

 

[Reppuzan]

This seems alright, especially since it's easier for users to find pages than blog posts.

 

[Assaltwaffle]

I'm always for making calculation resources easier to find. Should they be linked on the Calculations Introduction and References page?

 

[Ultima_Reality]

I agree with this suggestion

 

[Amelia_Lonelyheart]

I think ArbitraryNumbers storm calc blog is also good to be added to the list. It can be extremely informative for new calcers and is very well structured.

 

[ArbitraryNumbers]

https://vsbattles.fandom.com/wiki/User_blog:ArbitraryNumbers/Standard_Storm_calc

If it's not too much I would like to have that blog get some inclusion as well, if it hasn't been done already.

EDIT: Ninja'd by Dark.

 

[Antvasima]

@Assaltwaffle

Yes, that seems like a good idea, and I would link to them via the list in the front page as well.

 

[Antvasima]

I am fine with including the storm calculation blog. I had forgotten about that.

 

[Antvasima]

I will wait for a bit more input before handling this, to be on the safe side.

 

[Soldier_Blue]

I agree with this. I also agree with Darkanine's suggestion on the storm blog.

 

[Antvasima]

Okay. I will handle this after I am done with the daily backlog.

 

[Thebluedash]

I agree with this. Should help a lot of people.

 

[Antvasima]

I have now copied the blog contents to new pages, and linked to them in the front page and wiki navigation bar:

Earthquake Power Chart

Explosion Radius/Area

Mountain and Island level requirements

Standard Storm calculations

I would appreciate if somebody would be willing to update the Calculations Introduction and References page accordingly.

 

[Kepekley23]

I agree with the suggestions as well.

 

[ArbitraryNumbers]

I think I've found an issue with my storm blog.

You see, they all assume the storm cloud is 30,000 ft.

The calculation in this forum thread, which attempted a hypothetical calc of a "standard" storm, used a height of 15 kilometers, a width of 10 km, and a length of 10 km.

http://forum.weatherzone.com.au/ubbthreads.php/topics/1147886/How_much_energy_is_in_a_thunde

The storm got 1.687 terajoules, from this standard storm. Quite handily blowing all of the values on my blog out of the water.

 

[Kepekley23]

That IS an issue.

What should we do now?

 

[ArbitraryNumbers]

Well on one hand it's pretty ridiculous for a storm that only covers an area of 550 meters to be 13,000 meters tall.

It's also pretty ridiculous for a storm that covers the entire planet to be 13 km tall (maybe)?

So I think establishing some mid, high, and low for the according values should be fine.

 

[Antvasima]

Okay. Please tell me whenever you need the Standard Storm calculations page opened for editing.

 

[Antvasima]

You can ask DontTalk to help you out, if you wish.

 

[ArbitraryNumbers]

Okay, false alarm.

"Now lets assume a modest density for air, which is variable with height (decreasing), so hence in the US standard atmosphere at the surface you have 1.225 kg/m^3, at altitude a 5th of the pressure, so hence lets take a mean value of say 0.75kg/m^3 for the depth the cloud.

So by mass 1.125x10^12 kg.

Assume all energy is yielded and the CAPE is a modest 1500J/kg: 1.687 Terajoules"

So not only did he use a different cloud density to find the mass, but 13,000 meters isn't that much lower than 15,000 meters, and he somehow got 1.687 terajoules by multiplying 1.125x10^12 by 1,500 (The actual result would only 1.6875e+15 joules).

EDIT: He didn't multiply incorrectly. I just misinterpreted terajoules as teratons.

 

[Antvasima]

Okay. Thank you for the update.