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How do you calculate the crushing of a human head inside a helmet?

Well we already have the values for the skull itself.

Now all that's left is to figure out is the volume of the helmet itself. Figure out how heavy medieval helmets are in general, then you figure out the density of the helmet's material.

To find the volume, it's as follows: Volume= Mass/Density of material

Now you need to find the compressive strength of the helmet's material (Since you're crushing it), then slap it onto the helmet's volume and boom. You get the value for crushing helmeted skulls.

Medieval helmets were generally 2-4 kg (I'll just use an average of 3 kg) and were primarily made of iron and steel. Let's just use steel as that is an alloy of iron. Steel has a density of 7900 kg/m^3 (Based on the average of 7850-8050 kg/m^3)

Using this handy calculator, the volume comes out at 379.747 cm^3.

Compressive strength (Also pulverization strength) of steel is anywhere between 300-1000 J/cc, I'll just assume 650 J/cc as it's supposed to be higher than Steel's low-end compressive strength (AKA violent frag) of 568.5 J/cc.

650*379.747= 246,835.55 J (Wall level)

Combine that with 105,931 joules for crushing skulls and the total yield comes to 352,766.55 J (Wall level).

So yeah, it's not exceeding Wall level anytime soon.
 
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