If he literally folded the stainless steel door in half? Then yes. (see below)
BUT there is literally 0 indication that he did so.
If you can prove he did, the math is here:
To find the thickness, simply do volume/area. Using the weight of a door will bypass calculating the hollowness.
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^^
source shows a height and width of 58 inches and 33 5/8 inches, or an area of 1.25822329 m^2, or 1950.25 in^2
a quick google search gives a common weight of 36 lbs, which using steel (7580 kg/m^3) as a material that would be 131.46 in^3
1950.25 in^2/131.46 in^3 is about 0.0674 inches thick.
To find the cross sectional area, multiply width by thickness
0.0674 x 33 5/8 = 2.266325 in^2.
Another quick google has Stainless Steel yield strength MPa of 215 MPa.
2.266325 in^2 x 215 MPa = 314360.581 newtons, or ~32 Metric Tons (Class 50)